Mathematitian needed.How much extra weight is added to a transom for each added inch of setback? Is there a calculation I can do to figure this out?Why we're at it, does anyone know the calculation to do to figure out recommended horsepower for a boat?Thanks,Jim
I believe the number you will end up with is actually torque (in/lbs in this case). Torque = Force x Moment if I remember correctly. Force is the weight of the engine and Moment is the length of the bracket....in a nutshell. I'm sure it's more complicated than that due the dimension of the surface where the bracket mounts to the transom, but that's a start.
I always heard the simplest way is for every 6" you go back off the transom you add 1/2 the engine weight. So if you go back 6" on a 200 lb motor, the actual weight would be 300 lbs.
Quote from: "gw204"Torque = Force x Moment if I remember correctly. Force is the weight of the engine and Moment is the length of the bracket....in a nutshell. You are correct in that assumption, Jim.And that leads to your recalulation of the CG. It's important to know for the prediction of how your hull will now handle as opposed to what the original designer had in mind. What is really happening (as your numbers show) is that the transom will now have forces acting on it that it may have never been designed for, by the engineer. This is the real issue here. If we assume that the force (weight of the engine) acts downward on the transom (in reality it also cantilevers out over the top) the transom is resisting that force through compression. Since it also sticks out over the back, the transom must resist that twisting force(bottom pushed forward, top pulled rearward) also. By moving the motor back, you have greatly increased that twisting force on the transom (resisting the moment) by both the weight of the engine and the moment arm (bracket) times the increased offset distance. So the really important factor IMHO is, will the transom resist the new forces acting on it. We haven't even touched the additional forces that act on all transoms generated by the running of the engine itself. I've been pretty lucky in the fact that my stock transom has done just that. My engine resides a full 26" behind the transom so "knock on wood" literally. since I'm not really adding any weight to the boat, rather just changing the Center of Gravity Right again, so now you can redistribute your loading to allow for that (and hopefully move the CG closer to its original position) and help with the handling.Nice website (CG) for dummies like me. Thanks and good luck.Jim
Torque = Force x Moment if I remember correctly. Force is the weight of the engine and Moment is the length of the bracket....in a nutshell.